通信人家园

标题: [求助]哪位高人知道SDH中回溯(crankback)功能的原理是怎样的,帮忙介绍下吧,谢谢!  [查看完整版帖子] [打印本页]

时间:  2007-1-24 14:59
作者: zgz2006     标题: [求助]哪位高人知道SDH中回溯(crankback)功能的原理是怎样的,帮忙介绍下吧,谢谢!

<p>如题,请高人赐教</p><p><span style="FONT-SIZE: 10.5pt; FONT-FAMILY: 宋体; mso-bidi-font-size: 12.0pt; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'; mso-bidi-font-family: 'Times New Roman'; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA;">“从提高连接建立成功概率,提高用户满意度的角度出发,测试网络是否具有<span lang="EN-US" style="FONT-SIZE: 10.5pt; FONT-FAMILY: 'Times New Roman'; mso-bidi-font-size: 12.0pt; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA; mso-fareast-font-family: 宋体;">Crankback</span><span style="FONT-SIZE: 10.5pt; FONT-FAMILY: 宋体; mso-bidi-font-size: 12.0pt; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'; mso-bidi-font-family: 'Times New Roman'; mso-font-kerning: 1.0pt; mso-ansi-language: EN-US; mso-fareast-language: ZH-CN; mso-bidi-language: AR-SA;">能力,即回溯到源节点或中间节点(一般是域边界节点)进行重路由。</span>”这句话应该如何理解,比如A,B,C,D互联,有条A到D的业务,如果B,C间的链路出现问题,则重新建立一条啊A,X,C的链路(X为任何网元,也可能是B),是这样理解的吗?????</span></p>




通信人家园 (https://www.txrjy.com/) Powered by C114