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标题: [求助]关于摩托CDMA基站设备及CDMA相关问题  [查看完整版帖子] [打印本页]

时间:  2007-11-15 18:03
作者: jiansky     标题: [求助]关于摩托CDMA基站设备及CDMA相关问题

<p>求教西红柿大侠几个关于CDMA的问题:</p><p>&nbsp;&nbsp; 1.关于联通C网基站中的载波、信道及PN之间的关系,还有与一个基站覆盖区的用户数的关系?</p><p>  也就是在实际通信中用户的话音或数据信息是怎样通过信道及载波传输的?</p><p>2。不知你有没有摩托C网设备的资料,能否给我发一些,学习一下,谢谢了。我的邮箱是<a href="mailto:zhangxiaofeng-1984@163.COM">zhangxiaofeng-1984@163.COM</a></p>
时间:  2007-11-15 18:55
作者: lily6189

&nbsp;<div vshape="_x0000_s3074"><div class="O" style="TEXT-ALIGN: justify; mso-line-spacing: &quot;100 20 0&quot;; mso-margin-left-alt: 216; mso-char-wrap: 1; mso-kinsoku-overflow: 1;"><nobr><span style="FONT-SIZE: 125%;"><span style="FONT-SIZE: 70%; LEFT: -10.88%; FONT-FAMILY: Wingdings; POSITION: absolute; TOP: 0.39em; TEXT-ALIGN: left; mso-special-format: bullet;">(</span></span><span style="FONT-SIZE: 125%; FONT-FAMILY: 宋体; mso-fareast-font-family: 宋体; mso-hansi-font-family: &quot;Times New Roman&quot;;"><b>使用</b></span><span lang="EN-US" style="FONT-SIZE: 125%; mso-fareast-font-family: 宋体; mso-hansi-font-family: &quot;Times New Roman&quot;; mso-fareast-language: ZH-CN;"><b>N</b></span><span style="FONT-SIZE: 125%; FONT-FAMILY: 宋体; mso-fareast-font-family: 宋体; mso-hansi-font-family: &quot;Times New Roman&quot;;"><b>码的目的: </b></span></nobr></div><div class="O1" style="TEXT-ALIGN: justify; mso-line-spacing: &quot;100 20 0&quot;; mso-margin-left-alt: 468; mso-char-wrap: 1; mso-kinsoku-overflow: 1;"><span><span style="FONT-SIZE: 65%; LEFT: -3.48%; FONT-FAMILY: Wingdings; POSITION: absolute; TOP: 0.49em; TEXT-ALIGN: left; mso-special-format: bullet;">&sup2;</span></span><span style="FONT-FAMILY: 宋体; mso-fareast-font-family: 宋体; mso-hansi-font-family: &quot;Times New Roman&quot;;"><b>数据加扰,使信息数据信号</b></span><span style="FONT-FAMILY: &quot;Times New Roman&quot;; mso-fareast-font-family: 宋体; mso-hansi-font-family: &quot;Times New Roman&quot;;"><b>“</b></span><span style="FONT-FAMILY: 宋体; mso-fareast-font-family: 宋体; mso-hansi-font-family: &quot;Times New Roman&quot;;"><b>噪声</b></span><span style="FONT-FAMILY: &quot;Times New Roman&quot;; mso-fareast-font-family: 宋体; mso-hansi-font-family: &quot;Times New Roman&quot;;"><b>”</b></span><span style="FONT-FAMILY: 宋体; mso-fareast-font-family: 宋体; mso-hansi-font-family: &quot;Times New Roman&quot;;"><b>化;并可保证各用户信号间尽可能正交; </b></span></div><div class="O1" style="TEXT-ALIGN: justify; mso-line-spacing: &quot;100 20 0&quot;; mso-margin-left-alt: 468; mso-char-wrap: 1; mso-kinsoku-overflow: 1;"><span><span style="FONT-SIZE: 65%; LEFT: -3.48%; FONT-FAMILY: Wingdings; POSITION: absolute; TOP: 0.49em; TEXT-ALIGN: left; mso-special-format: bullet;">&sup2;</span></span><span style="FONT-FAMILY: 宋体; mso-fareast-font-family: 宋体; mso-hansi-font-family: &quot;Times New Roman&quot;;"><b>扩譜,将低速率信息比特流转化为</b></span><span style="mso-fareast-font-family: 宋体; mso-hansi-font-family: &quot;Times New Roman&quot;;"><b>1.2288M</b></span><span style="FONT-FAMILY: 宋体; mso-fareast-font-family: 宋体; mso-hansi-font-family: &quot;Times New Roman&quot;;"><b>符号流,增强抗干扰能力。 </b></span></div><div class="O" style="TEXT-ALIGN: justify; mso-line-spacing: &quot;100 20 0&quot;; mso-margin-left-alt: 216; mso-char-wrap: 1; mso-kinsoku-overflow: 1;"><nobr><span style="FONT-SIZE: 125%;"><span style="FONT-SIZE: 70%; LEFT: -10.88%; FONT-FAMILY: Wingdings; POSITION: absolute; TOP: 0.39em; TEXT-ALIGN: left; mso-special-format: bullet;">(</span></span><span style="FONT-SIZE: 125%; FONT-FAMILY: 宋体; mso-fareast-font-family: 宋体; mso-hansi-font-family: &quot;Times New Roman&quot;;"><b>采用</b></span><span lang="EN-US" style="FONT-SIZE: 125%; mso-fareast-font-family: 宋体; mso-hansi-font-family: &quot;Times New Roman&quot;; mso-fareast-language: ZH-CN;"><b>N</b></span><span style="FONT-SIZE: 125%; FONT-FAMILY: 宋体; mso-fareast-font-family: 宋体; mso-hansi-font-family: &quot;Times New Roman&quot;;"><b>码的原因: </b></span></nobr></div><div class="O1" style="TEXT-ALIGN: justify; mso-line-spacing: &quot;100 20 0&quot;; mso-margin-left-alt: 468; mso-char-wrap: 1; mso-kinsoku-overflow: 1;"><span><span style="FONT-SIZE: 65%; LEFT: -3.48%; FONT-FAMILY: Wingdings; POSITION: absolute; TOP: 0.49em; TEXT-ALIGN: left; mso-special-format: bullet;">&sup2;</span></span><span style="FONT-FAMILY: 宋体; mso-fareast-font-family: 宋体; mso-hansi-font-family: &quot;Times New Roman&quot;;"><b><u>若使用完全随机的序列进行加扰、扩频,则解调时无法恢复信息比特。</u></b></span><span style="FONT-FAMILY: 宋体; mso-fareast-font-family: 宋体; mso-hansi-font-family: &quot;Times New Roman&quot;;"><b>所采用的扩譜序列既要有高度的随机特性,又能可控地复现;</b></span><span lang="EN-US" style="mso-fareast-font-family: 宋体; mso-hansi-font-family: &quot;Times New Roman&quot;; mso-fareast-language: ZH-CN;"><b>N</b></span><span style="FONT-FAMILY: 宋体; mso-fareast-font-family: 宋体; mso-hansi-font-family: &quot;Times New Roman&quot;;"><b>序列满足这些要求</b></span><span style="DISPLAY: none; FONT-SIZE: 79%; mso-special-format: lastCR;"><font size="2">
                                </font></span></div></div>
时间:  2007-11-15 19:15
作者: icomain

<p>路过!</p>
时间:  2007-11-16 14:45
作者: 西红柿

<p>资料版和无线版有不少资料,,,</p><p></p><p>可以下一些学习一下。。。</p>
时间:  2007-11-17 23:26
作者: snowinmay

用户数是根据话务量模型计算的,你这个问题问的有点宽泛,还是先看点CDMA的资料,看几个CDMA的设计,有针对性的提出问题来探讨还好些。




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