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注册:2010-10-17
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发表于 2010-10-19 21:27:48 |只看该作者 |倒序浏览
In a 4 antenna (Nt  = 4) system operating at 10 dB with Tfb  = 100 bits, for example, it is near-optimal to have 5 users (arbitrarily chosen from a larger user set) feed back B = 20 bits each. This provides a sum rate of 9.9 bps/Hz, whereas 10 users with B = 10 with and 25 users with B = 4(i.e., operating with less accurate CSI ) provide sum rates of only 8.5 and 4.6, respectively

这里的sum-rate of 9.9bps/Hz是怎么计算出来的,有没有明白的,给我讲讲,不胜感激……

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