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注册:2003-1-13
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发表于 2009-8-9 20:58:24 |只看该作者 |正序浏览
3GPP TS44.065 关于SNDCP PDU DATA重组的说明部分有如下描述:
6.7.4.2
Receive Subsequent Segment state
If an SN‑UNITDATA PDU is received with the F bit set to 1, and if DCOMP or PCOMP is different from those in the first segment, then the SN‑UNITDATA PDU and all previous segments belonging to the same N‑DU shall be discarded. The Received First Segment state shall be entered if the M bit is set to 0, otherwise the Discard state shall be entered.
RSS(Receive Subsequent Segment state状态下,如果收到F = 1 PDU,并且DCOMPPCOMP和此前RFS(Receive First Segment state状态保留的值不一致,那么丢弃此前所有PDU和当前收到的PDU,如果此PDU M = 0,进入RFS状态,否则进入DSC(Discard state状态
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此状态下,根据协议描述,如果F=1 并且DCOMP、PCOMP和此前RFS状态保留的不一致才丢弃当前PDU以及此前的PDU。我对此不是十分明白,按照该描述似乎还有一种情况就是F=1,但是DCOMP、PCOMP和前面RFS状态收到的PDU一致。那么此时如何处理?

或者请高手就RSS(Receive Subsequent Segment state)状态下,SNDCP协议栈对于后续SN-PDU data的处理是如何进行的加以详解。谢谢了!

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